In a parallelogram ABCD of area 72 sq cm, the sides CD and AD have lengths 9 cm and 16 cm, respectively. Let P be a point on CD such that AP is perpendicular to CD. Then the area, in sq cm, of triangle APD is
Area of the parallelogram ABCD = base × height
CD × AP = 72
9 × AP = 72
AP = 8
In right triangle, APD
DP2 = AD2 − AP2
DP2 = 162 − 82
DP = 8√3
Area of triangle APD = 1/2 × AP × PD
= 32√3
The correct option is C.