The number of integers x such that 0.25 < 2^{x} < 200, and 2^{x} + 2 is perfectly divisible by either 3 or 4, is

### Answer

0.25 ≤ 2^{x} < 200

Possible values of x satisfying the above inequality are –2, –1, 0, 1, 2, 3, 4, 5, 6, 7.

When x = 0, 1, 2, 4 and 6, 2^{x} + 2 is divisible by 3 or 4.

So, the number of values of x is 5.

**The correct answer is 5.**