Three times the first of three consecutive odd integers is 3 more than twice

Three times the first of three consecutive odd integers is 3 more than twice the third. What is the third integer?

  1. 5
  2. 9
  3. 11
  4. 15

Answer

Let the three odd integers be: x, x + 2 and x + 4

According to the question,

3x = 2(x + 4) + 3

3x = 2x + 8 + 3

x = 11

Third integer is x + 4 = 11 + 4 = 15.

The correct option is D.