Linear Equations

Using only 2, 5, 10, 25, and 50 paisa coins, what will be the minimum number of coins required to pay exactly 78 paise, 69 paise and Rs. 1.01 to three different persons?

  1. 17
  2. 18
  3. 19
  4. 20

Answer

For 69 paise, 1*50 + 1*10 + 1*5 + 2*2 = 5 coins

For 78 paise, 1*50 + 2*10 + 4*2 = 7 coins

For 101 paise, 1*50 + 1*25 + 2*10 + 3*2 = 7 coins

Total minimum coins required = 5 + 7 + 7 = 19

The correct option is C.