There are 24 equally spaced points lying on the circumference of a circle. What is the maximum number of equilateral triangles that can be drawn by taking sets of three points as the vertices?
Complete circle makes 360 degrees at the centre.
Each of the 24 equally spaced points subtend an angle at the centre of the circle = 360/24 = 15 degrees
Two consecutive vertices of an equilateral triangle subtend and angle of 120 degrees at the centre.
Number of possible triangles = 120/15
The correct option is C.