The coordination number and the oxidation state of the element E

The coordination number and the oxidation state of the element E in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylene diamine) are, respectively

  1. 6 and 3
  2. 4 and 2
  3. 4 and 3
  4. 6 and 2

Answer

In the given complex [E(en)2(C2O4)]+NO2- ethylene diamine is a bidentate ligand and (C2O42–) oxalate ion is also bidentate ligand.

Therefore, co­ordination number of the complex is 6 i.e., it is an octahedral complex.

Oxidation number of E in the given complex is

x + 2 × 0 + 1 × (–2) = +1

x = 3

The correct option is A.