The coordination number and the oxidation state of the element E in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylene diamine) are, respectively
- 6 and 3
- 4 and 2
- 4 and 3
- 6 and 2
In the given complex [E(en)2(C2O4)]+NO2- ethylene diamine is a bidentate ligand and (C2O42–) oxalate ion is also bidentate ligand.
Therefore, coordination number of the complex is 6 i.e., it is an octahedral complex.
Oxidation number of E in the given complex is
x + 2 × 0 + 1 × (–2) = +1
x = 3
The correct option is A.