The following statement (p → q) → [(~p→q)→q] is
The following statement (p → q) → [(~p→q)→q] is:
- a tautology
- equivalent to ~p → q
- equivalent to p → ~q
- a fallacy
Answer
(p → q) → ((~p → q) → q)
= (p → q) → ((p ∨ q) → q)
= (p → q) → ((~p ∧ ~q) ∨ q)
= (p → q) → ((~p ∨ q) ∧ (~q ∨ q))
= (p → q) → (~p ∨ q)
= (p → q) → (p → q)
= T
The correct option is A.