A faster train takes one hour less than a slower train for a journey of 200 km
A faster train takes one hour less than a slower train for a journey of 200 km. If the speed of slower train is 10 km/hr less than that of faster train, find the speeds of two trains.
Answer
Let the speed of faster train be x km/hr.
∴ Speed of slower train = (x – 10) km/hr
200/(x - 10) - 200/x = 1
⇒ x2 – 10x – 2000 = 0
⇒ (x – 50) (x + 40) = 0
x = 50, –40 (rejected)
∴ Speed of faster train 50 km / hr
Speed of slower train 40 km / hr