Differential Equation
If (2 + sin x) dy/dx + (y + 1)cos x = 0 and y(0) = 1
If (2 + sin x) dy/dx + (y + 1)cos x = 0 and y(0) = 1, then y(π/2) is equal to
- 1/3
- -2/3
- -1/3
- 4/3
The differential equation which represents the family of curves
The differential equation which represents the family of curves y = c1ec2x where c1 and c2 are arbitrary constants, is
- yy'' = y'
- y'' = y'y
- y' = y2
- yy'' = (y')2
Let y(x) be the solution of the differential equation
Let y(x) be the solution of the differential equation (x log x)(dy/dx) + y = 2x log(x), (x≥1). Then y(e) is equal to
- 0
- 2e
- e
- 2
The solution of the equation d^2y/dx^2 = e^-2x is
The solution of the equation d2y/dx2 = e-2x is
- e-2x/4
- 1/4 * e-2x + cx2 + d
- e-2x/4 + cx + d
- 1/4 * e-4x + cx + d
The order and degree of the differential equation (1 + 3dy/dx)^2/3 = 4d^3y/dx^3 are
The order and degree of the differential equation (1 + 3dy/dx)2/3 = 4d3y/dx3 are
- (3, 3)
- (3, 1)
- (1, 2)
- (1, 2/3)