In the figure given below, PQRS is a parallelogram. PA bisects angle P and SA bisects angle S. What is angle PAS equal to?

- 60°
- 75°
- 90°
- 100°

**Answer**

Since PQRS is a parallelogram,

∠P + ∠S = 180°

PA bisects ∠P and SA bisects ∠S,

∠PSA + ∠APS = 180°/2 = 90°

In the triangle PAS

∠PAS + ∠PSA + ∠APS = 180°

∠PAS = 180° - 180°/2 = 90°

**The correct option is C.**