If the current I through a resistor is increased by 100% (assume that temperature remains unchanged), the increase in power dissipated will be

- 100%
- 200%
- 300%
- 400%

### Answer

If I is current and R is resistance then,

Power, P = I^{2}R

Power in first case, P_{1} = I^{2}R

100% increase in current means that current becomes 2I

Power in second case, P_{2} = (2I)^{2}R = 4I^{2}R

Now, increase in dissipated power = P_{2} – P_{1} = 4I^{2}R – I^{2}R = 3I^{2}R

Percentage increase in dissipated power = 3P_{1}/P_{1} × 100 = 300%

**The correct option is C.**