A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?

- 30 days
- 40 days
- 60 days
- 70 days

**Answer**

A's one day work = x

B's one day work = y

Let total work be 60 units.

x + y = 2 and 16x + 44y = 60

16x + 16y = 32 and 16x + 44y = 60

28y = 28

y = 1

B's one day work is 1 unit. So, 60 units of work can be completed by B in 60 days.

**The correct option is C.**