AB is a chord of a circle. The length of AB is 24 cm. P is the midpoint of AB. Perpendiculars from P on either side of the chord meets the circle at M and N respectively. If PM < PN and PM = 8 cm. then what will be the length of PN?

- 17 cm
- 18 cm
- 19 cm
- 20 cm
- 21 cm

**Answer**

P is midpoint of AB. So, AP = PB = AB/2 = 24/2 = 12

If two chords of a circle intersect at a point, then

AP × PB = PM × PN

12 × 12 = 8 x PN

PN = 18

**The correct option is B.**

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