Consider three mixtures - the first having water and liquid A in the ratio 1:2

Consider three mixtures - the first having water and liquid A in the ratio 1 : 2, the second having water and liquid B in the ratio 1: 3, and the third having water and liquid C in the ratio 1 : 4. These three mixtures of A, B, and C, respectively, are further mixed in the proportion 4 : 3 : 2. Then the resulting mixture has

  1. The same amount of water and liquid B
  2. The same amount of liquids B and C
  3. More water than liquid B
  4. More water than liquid A

Answer

First mixture has 2/3 A and the rest water. Second mixture has 3/4 B and the rest water. Third mixture has 4/5 C and the rest water.

The 3 mixtures are mixed in the ratio 4 : 3 : 2. Suppose you get 9 litres of mixture containing the three mixtures.

There will be 4(2/3) A, 3(3/4) B and 2(4/5) C. The remaining part would be water.

8/3 litres A, 9/4 litres B, 8/5 litres C

Water = 9 - (8/3 + 9/4 + 8/5) = 149/60 litres

Now, 149/60 < 8/3 and 149/60 > 9/4

∴ There is more water than B in the resultant solution.

The correct option is C.