If three positive real numbers x, y and z satisfy y - x = z - y and xyz = 4
If three positive real numbers x, y and z satisfy y - x = z - y and xyz = 4, then what is the minimum possible value of y?
- 2(1/4)
- 2(2/3)
- 2(1/3)
- 2(3/4)
Answer
y - x = z - y
2y = x + z
Therefore, x, y, z are in Arithmetic Progression
AM ≥ GM
(x+y+z)/3 ≥ (xyz)1/3
y ≥ 2(2/3)
The correct option is B.