In a certain examination, the number of students who passed, was three times the number of those who were rejected. If there had been 16 fewer candidates and if six more had been rejected, the number of those who passed and of those who were rejected would have been in the ratio 2 : 1. Find the number of candidates?
Let number of rejected students = x
So, number of passed students = 3x
Total number of students = 4x
With 16 fewer candidates and 6 more rejected, 22 (16+6) less would have passed.
3x - 22 = 2(x + 6)
3x - 22 = 2x + 12
x = 34
Number of candidates = 4x = 136
The correct option is C.