The minimum possible value of the sum of the squares of the roots

The minimum possible value of the sum of the squares of the roots of the equation x2 + (a + 3)x - (a + 5) = 0 is

  1. 1
  2. 2
  3. 3
  4. 4

Answer

x2 + (a + 3)x - (a + 5) = 0

α2 + β2 = (α + β)2 – 2αβ

= (-(a + 3))2 – 2(-(a + 5))

= a2 + 9 + 6a + 2(a + 5)

= a2 + 8a + 19

= (a + 4)2 + 3

The minimum value is 3, at a = -4.

The correct option is C.