The minimum possible value of the sum of the squares of the roots
The minimum possible value of the sum of the squares of the roots of the equation x2 + (a + 3)x - (a + 5) = 0 is
- 1
- 2
- 3
- 4
Answer
x2 + (a + 3)x - (a + 5) = 0
α2 + β2 = (α + β)2 – 2αβ
= (-(a + 3))2 – 2(-(a + 5))
= a2 + 9 + 6a + 2(a + 5)
= a2 + 8a + 19
= (a + 4)2 + 3
The minimum value is 3, at a = -4.
The correct option is C.