There are two containers A and B of milk solution. The ratio of milk and water

There are two containers A and B of milk solution. The ratio of milk and water in container A is 3 : 1 and in container B, it is 4 : 1. How many liters of container B solution has to be added to 20 lts of container A solution such that in the resulting solution the ratio of milk to water should be 19 : 6?

Solution

Percentage of milk in A = 3/4 = 75%

Percentage of milk in B = 4/5 = 80%

Percentage of milk in resultant solution = 19/25 = 76%

Applying the rule of alligation,

Volume in B : Volume in A  = (76% - 75%) : (80% - 76%) = 1 : 4

It is given that 20 litres of container A is added. So, the quantity of container B should be 5 litres.