A piece of ice, 100 g in mass is kept at 0°C. The amount of heat it requires to melt at 0°C is (take latent heat of melting of ice to be 333.6 J/g):
- 750.6 J
- 83.4 J
- 33360 J
- 3.336 J
Answer
When ice melts, it remains at 0°C (32°F), and the liquid water that is formed with the latent heat of fusion is also at 0°C.
Latent heat of melting of ice = 333.6 J/g
1 g of ice requires 333.6 J heat to melt. So, for 100 g of ice,
Amount of heat required = 100 g × 333.6 J/g = 33360 J
The correct option is C.