The number of aluminium ions present in 54 g of aluminium (atomic weight 27) is

- 2
- 18
- 1.2 x 10
^{24} - 1.1 x 10
^{24}

**Answer**

From mole concept, 27 g has 6.022×10^{23} ions.

54 g will have 2 x 6.0^{22}×10^{23} = 1.2 x 10^{24}

**The correct option is C.**