From the top of a building 90 m high, the angles of depression
From the top of a building 90 m high, the angles of depression of the top and the bottom of a tree are 30° and 45° respectively. What is the height of the tree?
- 30√3 m
- 90 - 30√3 m
- 90 + 30√3 m
- 60 + 30√3 m
Answer
Let distance between the building and tree be d. Let the height of tree be h.

DE = d and CD = h
tan 45° = 90/d
1 = 90/d
d = 90
tan 30° = (90-h)/d
1/√3 = (90-h)/d
d = (90-h)√3
90/√3 = 90 - h
h = 90 - 90/√3
h = 90 - 30√3
The correct option is B.