If log25 5 = a and log25 15 = b, then the value of log25 27 is
If log25 5 = a and log25 15 = b, then the value of log25 27 is
- 3(b+a)
- 3(1-b-a)
- 3(a+b-1)
- 3(1-b+a)
Solution
a + b = log25 5 + log25 15 = log25 75 = log25 25 + log25 3
a + b = 1 + log25 3
a + b - 1 = log25 3
log25 27 = 3 log25 3 = 3(a + b - 1)
The correct option is C.