If m% of m + n% of n = 2% of (m × n)
If m% of m + n% of n = 2% of (m × n), then what percentage of m is n?
- 25%
- 50%
- 75%
- 100%
Answer
We need to calculate the ratio n/m.
According to the question, we have:
(m/100) × m + (n/100) × n = 2/100 × (mn)
⇨ m2/100 + n2/100 = 2 mn / 100
Divide both sides by m2 and multiply by 100
So, 1 + (n/m)2 = 2(n/m)
Put (n/m) = x
So, x2 - 2x + 1 = 0
⇨ (x - 1)2 = 0
⇨ x = 1
So, x = n/m = 1
⇨ n = m
Therefore, n is (100% of m) or equal to m.
The correct option is D.