If the height of a right circular cone is increased by 200%
If the height of a right circular cone is increased by 200%, and the radius of the base is reduced by 50%, then the volume of the cone
- remains unaltered
- decreases by 25%
- increases by 50%
- increases by 25%
Answer
Volume of a cone of radius r and height h, is given by 1/3 πr2h = v (say).
Now, new height = h(1 + 200/100) = h(1 + 2) = 3h
and new radius = r(1 - 50/100) = r(1 - 1/2) = r/2
So, new volume = 1/3 π (r/2)2(3h)
= 3/4 × (1/3 πr2h)
= 3/4 × v = 0.75v
So, Reduction in volume = (v - 0.75v)/v
= 0.25 times = 25%
The correct option is B.