The total outer surface area of a right circular cone of height 24 cm
The total outer surface area of a right circular cone of height 24 cm with a hemisphere of radius 7 cm upon its base is
- 327 π
- 307 π
- 293 π
- 273 π
Answer
The cone and the hemisphere are as shown in the figure:

So, first we need to calculate the slant height (l) of the cone.
Slant height = √(242 + 72) (By Pythagoras theorem)
= √625 = 25 cm
Now, total outer surface area = outer surface area of hemisphere + outer surface area of cone
= πrl + 2πr2, where r = 7 cm and l = 25 cm
= 25×7π + 2×49π
= (175 + 98) π
= 273 π
The correct option is D.