Surface Chemistry

3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06 N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is:

  1. 54 mg
  2. 42 mg
  3. 36 mg
  4. 18 mg

Answer

Amount adsorbed

= (0.060 – 0.042) x 50 x 10–3 x 60

= 0.018 x 50 x 60 x 10–3

= 0.018 x 3 

= 0.054 gm

= 54 mg

Amount adsorbed per gram of activated charcoal = 54/3 = 18 mg

The correct option is D.