Freezing point of an aqueous solution is (-0.186)°C. Elevation of boiling point of the same solution is Kb = 0.512 °C, Kf = 1.86 °C, find the increase in boiling point.
- 0.186 °C
- 0.092 °C
- 0.0512 °C
- 0.2372 °C
We know ΔTb = mkb and ΔTf = mKf
ΔTb/ΔTf = Kb/Kf
Find ΔTb which would come 0.0512°C
The correct option is C.