The sum to infinity of the series 1 + 2/3 + 6/3^2 + 10/3^3
The sum to infinity of the series 1 + 2/3 + 6/32 + 10/33 + ... is
- 2
- 3
- 4
- 6
Answer
Let S = 1 + 2/3 + 6/32 + 10/33 + ...
S/3 = 1/3 + 2/32 + 6/33 + ..
S - S/3 = 1 + 1/3 + 4/32 + ...
2S/3 = 4/3 + 4/32/(1 - 1/3)
= 4/3 + 2/3
The correct option is B.