A ball whose kinetic energy is E, is projected at an angle of 45° to the horizontal. The kinetic energy of the ball at the highest point of its flight will be
Kinetic Energy, E = ½mv2
At the highest point, vertical component of velocity becomes zero and only the horizontal component is left that is given by
ux = u cosθ
θ = 45°, so cosθ = 1/√2
ux = u/√2
Kinetic energy E at the highest point = ½m(u/√2)2 = E/2
The correct option is C.