A particle has an initial velocity of 3i + 4j and an acceleration of 0.4i + 0.3j
A particle has an initial velocity of 3i + 4j and an acceleration of 0.4i + 0.3j. Its speed after 10s is
- 7(√2) units
- 10 units
- 7 units
- 8.5 units
Solution
Use equation of kinematics: v = u + at
Initial Velocity, u = 3i + 4j
Acceleration, a = 0.4i + 0.3j
Time, t = 10s
v = (3i + 4j) + 10(0.4i + 0.3j)
v = (3i + 4j) + (4i + 3j)
v = 7i + 7j
|v| = √(72+72) = 7(√2)
Correct option is A.