In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280
In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280. If current in primary coil is 4 A, then that in the secondary coil is
- 10 A
- 6 A
- 4 A
- 2 A
Answer
Use formula,
Ip/Is = Ns/Np
4/Is = 280/140
Is = 4/2 = 2
The correct option is D.