In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280. If current in primary coil is 4 A, then that in the secondary coil is

- 10 A
- 6 A
- 4 A
- 2 A

**Answer**

Use formula,

I_{p}/I_{s} = N_{s}/N_{p}

4/I_{s} = 280/140

I_{s} = 4/2 = 2

**The correct option is D.**