The height at which the acceleration due to gravity becomes g/9
The height at which the acceleration due to gravity becomes g/9 (where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is
- (√2)R
- R/2
- R/√2
- 2R
Answer
GM/(9R2) = GM/(R + h)2
3R = R + h
h = 2R
The correct option is D.