The maximum number of possible interference maxima
The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in young’s double-slit experiment is
- infinite
- five
- three
- zero
Answer
nλ = d sinθ
2nλ = 2d.sinθ
2d = 2λ given
2nλ = 2λ . sinθ
sin θ = n (n = 0, 1, 2, .... ∝)
The correct option is A.