The surface of a metal is illuminated with the light of 400 nm
The surface of a metal is illuminated with the light of 400 nm. The kinetic energy of the ejected photoelectrons was found to be 1.68 eV. The work function of the metal is (hc = 1240 eV.nm)
- 1.41 eV
- 1.51 eV
- 1.68 eV
- 3.09 eV
Answer
hc/λ = φ + (K.E.)max
1240/400 = φ + 1.68
φ = 1.41 eV
The correct option is A.