Largest value of min(2 + x^2, 6 - 3x), when x > 0, is

• Quant Quadratic

Largest value of min(2 + x², 6 - 3x), when x > 0, is

1. 1
2. 2
3. 3
4. 4

Answer

For minimum,

2 + x² = 6 - 3x

x² + 3x - 4 = 0

x = 1, -4

Since x > 0, so value occurs at x = 1.

At x = 1, 6 - 3x = 3.

The correct option is C.