What is the sum of all two-digit numbers that give a remainder of 3 when they are divided by 7?
Two digit number is of the form: 7a+3 (a = 1 to 13)
The number forms Arithmetic Progression with common difference of 7. First term is 10. Last term is 94.
Number of Terms = 13
Sum = n(a+l)/2 = (13*104)/2 = 676
The correct option is A.