What will be remainder when (67^{67} + 67) is divided by 68?

- 67
- 63
- 66
- 1

**Answer**

(x^{n} + 1) will be divisible by (x + 1) only when n is odd.

(67^{67} + 1) will be divisible by (67 + 1)

(67^{67} + 1) + 66, when divided by 68 will give 66 as remainder.

**The correct option is C.**