The compound C_{6}H_{12}O_{4} contains

- 22 atoms per mole
- twice the mass percent of H as compared to the mass percent of C
- six times the mass percent of C as compared to the mass percent of H
- thrice the mass percent of H as compared to the mass percent of 0

**Answer**

There are 6.022×10^{23} entities in 1 mole. So, option A is incorrect.

Atomic mass of Carbon = 12

Atomic mass of Hydrogen = 1

Atomic mass of Oxygen = 16

Molecular mass = (6 × 12) + (12 × 1) + (4 × 16)

= 72 + 12 + 64 = 148

Mass percentage of carbon = 72/148 = 49%

Mass percentage of hydrogen = 12/148 = 8%

Mass percentage of oxygen = 64/148 = 43%

**The correct option is C.**