A car travels first one-third of a certain distance with a speed of 10 km/hr
A car travels first one-third of a certain distance with a speed of 10 km/hr, the next one-third of the distance with the speed of 20 km/hr and the last one-third distance with a speed of 60 km/hr. The average speed of the car for the whole journey is
- 18 km/hr
- 24 km/hr
- 30 km/hr
- 36 km/hr
Answer
Let the total distance be 3x km. Now, average speed is given by
average speed = (total distance travelled) / (total time taken)
So, let times taken for the first, second and third halves of the journeys be t1, t2, and t3 respectively. Then,
t1 = x/10
t2 = x/20
t3 = x/60
So, average speed = x / (t1 + t2 + t3)
= x / (x/10 + x/20 + x/60)
= 3/ ((6 + 3 + 1)/60)
= (3×60)/10
= 18 km/hr
The correct option is A.