Time Distance

Arup and Swarup leave point A at 8 AM to point B. To reach B, they have to walk the first 2 km, then travel 4 km by boat and complete the final 20 km by car. Arup and Swarup walk at a constant speed of 4 km/hr and 5 km/hr respectively. Each rows his boat for 30 minutes. Arup drives his car at a constant speed of 50 km/hr while Swarup drives at 40 km/hr. If no time is wasted in transit, when will they meet again?

  1. At 9.15 AM
  2. At 9.18 AM
  3. At 9.21 AM
  4. At 9.24 AM
  5. At 9.30 AM

Answer

Both, Arup and Swarup leave at 8 AM.

Arup walks 2 km at the speed of 4 km/hr. He takes 30 minutes walking and then 30 minutes boating. He starts his car at 9:00 AM at the speed of 50 km/hr.

Swarup walks 2 km at the speed of 5 km/hr. He takes 24 minutes walking and then 30 minutes boating. He starts his car ar 8:54 AM at the speed of 40 km/hr.

When Arup and Swarup meets, distance traveled by them will be same. Time taken by Swarup will be 6 minutes more.

50 × t = 40 × (t+6)

5t = 4t + 24

t = 24 minutes

They will meet at 9:24 AM.

The correct option is D.