Arup and Swarup leave point A at 8 AM to point B. To reach B, they have to walk the first 2 km, then travel 4 km by boat and complete the final 20 km by car. Arup and Swarup walk at a constant speed of 4 km/hr and 5 km/hr respectively. Each rows his boat for 30 minutes. Arup drives his car at a constant speed of 50 km/hr while Swarup drives at 40 km/hr. If no time is wasted in transit, when will they meet again?

- At 9.15 AM
- At 9.18 AM
- At 9.21 AM
- At 9.24 AM
- At 9.30 AM

**Answer**

Both, Arup and Swarup leave at 8 AM.

Arup walks 2 km at the speed of 4 km/hr. He takes 30 minutes walking and then 30 minutes boating. He starts his car at 9:00 AM at the speed of 50 km/hr.

Swarup walks 2 km at the speed of 5 km/hr. He takes 24 minutes walking and then 30 minutes boating. He starts his car ar 8:54 AM at the speed of 40 km/hr.

When Arup and Swarup meets, distance traveled by them will be same. Time taken by Swarup will be 6 minutes more.

50 × t = 40 × (t+6)

5t = 4t + 24

t = 24 minutes

They will meet at 9:24 AM.

**The correct option is D.**