A thief running at 8 km/hr is chased by a policeman whose speed is 10 km/hr. if the thief is 100 m ahead of the policeman, then the time required for the policeman to catch the thief will be

- 6 min
- 3 min
- 2 min
- 4 min

**Answer**

The relative speed between police and thief = 10-8 = 2 km/h = 10/18 m/s

Distance between police and thief = 100 m

Time = Distance/Speed = 180 s = 3 min

**The correct option is B.**