In the figure given below, M is the mid-point of AB and ∠DAB = ∠CBA and ∠AMC = ∠BMD. Then the triangle ADM is congruent to the triangle BCM by

- SAS rule
- SSS rule
- ASA rule
- AAA rule

As M is the mod-point of AB, AM = MB.

Two angles, ∠DAB = ∠CBA and ∠AMC = ∠BMD, and included sides are equal. So, the triangle ADM is congruent to the triangle BCM by ASA rule.

**The correct option is C.**

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