In the figure given, LM is parallel to QR. If LM divides the triangle PQR such that area of trapezium LMRQ is two times the area of triangle PLM, then what is PL/PQ equal to?

- 1/3
- 1/√2
- 1/√3
- 1/2

**Answer**

Triangles PLM and PQR are similar. The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

Area (LMRQ) = 2 * Area (PLM)

Area (PQR) = Area (LMRQ) + Area (PLM) = 3 * Area (PLM)

**The correct option is C.**