The radius of the base of a right circular cone is increased by 15% keeping the height fixed. The volume of the cone will be increased by
Volume of a cone = πr2h, where r is the radius of base and h is the height of the cone.
So, let initial volume be = V1
Final volume, V2 = πR2h, where R = r(1 + 0.15) = 1.15r
So, V2 = 1.3225 πr2h
Increase in volume = (V2 - V1) /V1 × 100%
= (1.3225 πr2h - πr2h)/πr2h × 100% = 32.25%
The correct option is B.