A and B are two heavy steel blocks. If B is placed on the top of A, the weight increases by 60%. How much weight will reduce with respect to the total weight of A and B, if B is removed from the top of A?
Let the weight of A is 100 kg.
Then, when B is placed on top of A, weight = 100 + (60% of 100)
= 160 kg.
Now, if B is removed from top, then weight becomes 100 kg.
Reduction in weight = (160 - 100)/160 = 60/160
The correct option is D.