The values of x which satisfy the equation 5^1+x + 5^1–x = 26 are

• Numbers

The values of x which satisfy the equation 5^1+x + 5^1–x = 26 are

1. –1, 1
2. 0, 1
3. 1, 2
4. –1, 0

Answer

5^1+x + 5^1–x = 26

5.5^x + 5.5^-x = 26

Let 5^x = t

5(t + 1/t) = 26

5(t² + 1) = 26t

5t² - 26t + 5 = 0

5t² - 25t - t + 5 = 0

5t(t - 5) - (t - 5) = 0

(t - 5)(5t - 1) = 0

t = 1/5, 5

5^x = 1/5, 5

x = -1, 1

The correct option is A.