What is the value of (Quant Trigo #02)
What is the value of
![]()
- √2
- 2√2
- √2 tan x
- 0
Answer
1/(1 + cos x) + 1/(1 - cos x) = (1 - cos x + 1 - cos x)/((1 + cos x)((1 - cos x)))
= 2/(1 - cos2 x)
= 2/(sin2 x)
Therefore, (sin x)√[2/(sin2 x)] = √2
The correct option is A.