In a compound C, H and N atoms are present in 9:1:3.5 by weight

• Stoichiometry

In a compound C, H and N atoms are present in 9:1:3.5 by weight. Molecular weight of compound is 108. Molecular formula of compound is

1. C₉H₁₂N₃
2. C₃H₄N
3. C₆H₈N₂
4. C₂H₆N₂

Solution

Molar mass of compound = 108 grams

Total part by weight = 9 + 1 + 3.5 = 13.5

Weight of carbon = (9*108)/13.5 = 72 g

Number of carbon atoms = 72/12 = 6

Weight of hydrogen = (1*108)/13.5 = 8 g

Number of hydrogen atoms = 8/1 = 8

Weight of nitrogen = (3.5*108)/13.5 = 28 g

Number of nitrogen atoms = 28/14 = 2

Hence, molecular formula is C₆H₈N₂

The correct option is C.