In the reaction, 2Al (s) + 6HCl (aq)
In the reaction,
2Al (s) + 6HCl (aq) → 2Al3+ (aq) + 6Cl– (aq) + 3H2 (g)
- 6 L HCl (aq) is consumed for every 3 L H2(g) produced
- 11.2 L H2(g) at STP is produced for every mole HCl (aq) consumed
- 33.6 L H2(g) is produced regardless of temperature and pressure for every mole Al that reacts
- 67.2 L H2(g) at STP is produced for every mole Al that reacts
Answer
2Al (s) + 6HCl (aq) → 2Al3+ (aq) + 6Cl– (aq) + 3H2 (g)
At STP, 6 moles of HCl produces 3 moles or 3 × 22.4 lit of HCl
1 mole of HCl produces 3*22.4/6 = 11.2 lit of HCl
Again at STP, 2 moles of Al produces 3 moles or 3 × 22.4 lit of HCl
or 1 mole of Al produces 3*22.4/2= 33.6 lit of HCl
The correct option is C.