A function f from the set of natural numbers to integers
A function f from the set of natural numbers to integers defined by
f(n) = (n-1)/2, when n is odd
f(n) = -n/2, when n is even
- one-one and onto both
- one-one and but not onto
- neither one-one nor onto
- onto but not one-one
Solution
If n is odd, let n = 2k - 1
f(2k1 - 1) = f(2k2 - 1)
2k1 - 1 + 1/2 = 2k2 - 1 + 1/2
k1 = k2
f(n) is one-one function, if n is odd.
If n is even, let n = 2k
f(2k1) = f(2k2)
k1 = k2
f(n) is one-one function, if n is even.
Also, f'(n) is increasing, when n is odd and f'(n) is decreasing, when n is even.
The correct option is A.